A geometry problem by Jayesh Agrawal
Geometry
Level
3
In a triangle PQR, PQ=QR. A and B are the midpoints of QR n PR resp. A circle passes through P, Q, A and B. Then which of the following is true.
None of these
Angle QRP =90*
PQR is right isosceles triangle
PQR is equilateral triangle
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1 solution
if PQAB is cyclic then by secant theorem we can see that RQ and `RP are 2 secants from the same point so :( AR ) * (RQ) = (RB) * (RP) this follows QR = PR and already PQ = QR so , PQ = QR = PR