two externally tangent circles of radii R1 and R2 are internally tangent to a semicircle of radius 1 then (given that R1 is not equal to R2)
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2R1 is less than or equal to 1, 2R2 is less than 1, (as both cannot be less than or equal to 1) therefore 2R1 + 2R2 is less than 1+1=2, therefore, R1+R2. <1 so the first three options are out.