A geometry problem by mario dawi

Geometry Level 3

A ship’s sonar locates a treasure chest at a 12 ° angle of depression. A diver is lowered 40 meters to the ocean floor. How far (to the nearest meters) does the diver need to swim along the ocean floor to get the treasure chest?

x=105 x=166 x=222 x=188

Mario Dawi by mario dawi , 22, Canada

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2 solutions

tan ⁡ 12 = 40 x \tan 12 = \dfrac{40}{x}

x = 40 tan ⁡ 12 ≈ 188 x=\dfrac{40}{\tan 12} \approx \boxed{188}

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Marta Reece
Jun 23, 2017

40 x = tan ⁡ 1 2 ∘ \dfrac {40}x=\tan12^\circ

x = 40 tan ⁡ 1 2 ∘ = 188 x=\dfrac{40}{\tan12^\circ}=\boxed{188}

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