A geometry problem by A Former Brilliant Member

Geometry Level pending

Two sides of a triangle are 119 m and 120 m, respectively. The perimeter is 408 m. What is the area of the triangle in square meters?

Try some of my problems: Math Problems - Set 1 .


The answer is 7140.

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A Former Brilliant Member by A Former Brilliant Member

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1 solution

Relevant wiki: Area of Triangles - Heron's Formula

the third side is 408 - 119 - 120 = 169 m

By Heron's Formula ,

S = S= 408 2 = 204 \frac{408}{2}=204

A = ( s ) ( s − a ) ( s − b ) ( s − c ) = ( 204 ) ( 85 ) ( 84 ) ( 35 ) = 7140 m 2 A=\sqrt{(s)(s-a)(s-b)(s-c)}=\sqrt{(204)(85)(84)(35)}=7140m^2

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