A geometry problem by A Former Brilliant Member

Geometry Level pending

The shortest side of an isosceles triangle is 8 8 cm. The included angle between the equal sides is 40 ° 40° . Find the area of the triangle in c m 2 cm^2 rounded to the nearest integer.


The answer is 44.

A Former Brilliant Member by A Former Brilliant Member

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2 solutions

Marta Reece
Apr 18, 2017

Half of the base is 4 4 . Half of the top angle is 2 0 ∘ 20^\circ . Height h = 4 tan ⁡ ( 2 0 ∘ ) ≈ 10.99 h=\frac{4}{\tan(20^\circ)}\approx10.99

A = 4 × h ≈ 44 A=4\times h\approx44

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