A geometry problem by A Former Brilliant Member

Geometry Level pending

The height and diameter of the right circular cylinder shown above is 10 10 and 8 8 , respectively. Point A A lies on the circumference of the bottom of the cylinder while point O O is the center of the top of the cylinder. What is the shortest distance between O O and A A ? Give your answer correct to 2 2 decimal places.


The answer is 10.77.

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1 solution

By pythagorean theorem ,

O A = 1 0 2 + 4 2 = 100 + 16 = 116 = OA=\sqrt{10^2+4^2}=\sqrt{100+16}=\sqrt{116}= 10.77 \boxed{10.77}

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