area of a triangle

Geometry Level pending

In rectangle A B C D ABCD , A B = 10 AB=10 and A D = 20 AD=20 . Point M M is the midpoint of A D AD . What is the area of △ A M C \triangle AMC ?


The answer is 50.

A Former Brilliant Member by A Former Brilliant Member

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2 solutions

A = 1 2 b h = 1 2 ( 10 ) ( 10 ) = 1 2 ( 100 ) = \large A=\dfrac{1}{2}bh=\dfrac{1}{2}(10)(10)=\dfrac{1}{2}(100)= 50 \color{#D61F06}\boxed{\large 50}

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Δ A M C = 1 2 ⋅ A M ⋅ D C = 1 2 ⋅ 10 ⋅ 10 = 50 \Delta AMC = \frac { 1 }{ 2 } \cdot AM \cdot DC = \frac { 1 }{ 2 } \cdot 10 \cdot 10 = 50

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