A geometry problem by A Former Brilliant Member

Geometry Level 3

The figure shown above is a semicircle with diameter of 12. The measure of arc A C AC is 13 5 135^\circ . Point D D is the midpoint of arc A C AC . Find the area of the shaded region. If your answer is in the form a b π \dfrac{a}{b} \pi , where a a and b b are positive coprime numbers, find a + b a+b .


The answer is 11.

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1 solution

Since D O A = C B O = 135 2 = 67. 5 \angle DOA = \angle CBO = \dfrac{135}{2}=67.5^\circ , O D B C OD \parallel BC .

Since D C B \triangle DCB and C B O \triangle CBO share the same base ( B C ) (BC) and height, they have equal areas.

Therefore, the area of the shaded region is the area of the sector C B O CBO and that is 45 360 π ( 6 2 ) = 9 2 π \dfrac{45}{360} \pi (6^2)=\dfrac{9}{2} \pi

Finally,

a + b = 9 + 2 = a+b=9+2= 11 \boxed{11}

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