Similar triangles

Geometry Level 3

In the diagram below, the top side of a square is extended to the right, the end of which is then connected to the lower left vertex of the square. This line segment is divided into two parts: the part with length 30 inside the square and the part with length 10 outside.

What is the side length of the square?


The answer is 24.

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1 solution

Relevant wiki: Similar Triangles Problem Solving - Basic

Let x = A B x=AB .

Since C E F D E A \triangle CEF \sim \triangle DEA , we have, C E E D = 10 30 = 1 3 \dfrac{CE}{ED}=\dfrac{10}{30}=\dfrac{1}{3} \implies E D = 3 ( C E ) ED=3(CE)

That means E D = 3 4 x ED=\dfrac{3}{4}x . Applying Pythagorean theorem on D E A \triangle DEA , we have

x 2 + ( 3 4 x ) 2 = 3 0 2 x^2+\left(\dfrac{3}{4}x\right)^2=30^2

x 2 + 9 16 x 2 = 900 x^2+\dfrac{9}{16}x^2=900

25 16 x 2 = 900 \dfrac{25}{16}x^2=900

x 2 = 16 25 ( 900 ) x^2=\dfrac{16}{25}(900)

x 2 = 576 x^2=576

x = 576 = x=\sqrt{576}= 24 \large \color{#D61F06}\boxed{24}

i thought about this solution too, but i ended up solving this system : (h + x)^2 +h^2 = 1600, y^2 + x^2 = 100, h^2 + (h-y)^2 = 900, where h is the side lenght of the square x,y the sides of hypotenuse 10 triangle.

aaaaaaa aaaaaa - 3 years, 11 months ago

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Your solution is also correct, but it is longer.

A Former Brilliant Member - 3 years, 11 months ago

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