A geometry problem by Mateus Gomes

Geometry Level 3

For z = 1 2 ( 1 + i ) z = \dfrac1{\sqrt2} (1+i) , the value of k = 1 60 z k \displaystyle \left | \sum_{k=1}^{60} z^k \right| is equal to A + B B \sqrt{A + B\sqrt B } , where A A and B B are positive integers. Find A + B A+B .

Clarification : i = 1 i = \sqrt{-1} .


The answer is 6.

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1 solution

Andreas Wendler
Feb 12, 2016

XPLORE delivers with "abs(sum((1/sqrt(2)*(1+î))^k,k=1 to 60))" value 2.61313 which is squared 6.82843. Now determine the difference with 4 and again the square. We get value 8 equals B^3. Solution is 4+2=6.

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