A geometry problem by Rajdeep Dhingra

Geometry Level 3

O A B C i s a r h o m b u s w h o s e 3 v e r t i c e s A , B a n d C l i e s o n a c i r c l e w i t h c e n t r e O . I f t h e r a d i u s o f c i r c l e i s 10 c m , f i n d t h e a r e a o f r h o m b u s . OABC\quad is\quad a\quad rhombus\quad whose\quad 3\quad vertices\quad A,B\quad and\quad C\quad lies\quad \\ on\quad a\quad circle\quad with\quad centre\quad O.\quad If\quad the\quad radius\quad of\quad circle\quad is\quad \\ 10\quad cm,\quad find\quad the\quad area\quad of\quad rhombus.

75 3 75\sqrt { 3 } 50 3 50\sqrt { 3 } 100 100 100 3 100\sqrt { 3 }

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3 solutions

Rajdeep Dhingra
Jan 2, 2015

I n t h e G i v e n f i g u r e Δ O C B O C = O B = 10 c m ( R a d i u s ) O C = C B S i d e s o f r h o m b u s Δ O C B i s e q u l a t e r a l h e n c e a r e a = 25 3 A r e a o f r h o m b u s = 50 3 In\quad the\quad Given\quad figure\quad \Delta OCB\\ OC=OB=10\quad cm\quad (\quad Radius)\\ OC\quad =\quad CB\quad Sides\quad of\quad rhombus\\ \Delta OCB\quad is\quad equlateral\quad \\ hence\quad area\quad =\quad 25\sqrt{ 3 }\\ Area\quad of\quad rhombus\quad =\quad 50\sqrt{ 3 }

Ea![](https://d18l82el6cdm1i.cloudfront.net/uploads/LfKFAWwxVd-image.jp

Your link is not complete.Your solution is down here.

Rajdeep Dhingra - 6 years, 4 months ago

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Thanks a lot !

Venkata Karthik Bandaru - 6 years, 3 months ago

good writing buddy

Kaustubh Miglani - 5 years, 5 months ago
Fox To-ong
Jan 7, 2015

area of rhombus = 2 area of equilateral triangle whose sides = 10

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