A geometry problem by Rama Devi

Geometry Level 2

If the angles of a pentagon are in the ratio 1:3:6:7:10 , then the smallest angle is ?


The answer is 20.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Siddharth Singh
Apr 25, 2015

Sum of all the angles of the pentagon is 540.Therefore - x+3x+6x+7x+10x=540. x=20 and it is the smallest angle.

Noel Lo
Apr 27, 2015

540/(1+3+6+7+10) = 540/27 = 20

Since the ratio is 1 : 3 : 6 : 7 : 10 1:3:6:7:10 , the total is 1 + 3 + 6 + 7 = 27 1+3+6+7=27 . The sum of the interior angles of pentagon is 54 0 540^\circ . So the smallest angle is

1 27 ( 540 ) = \dfrac{1}{27}(540)= 2 0 \boxed{20^\circ}

Dipak Prajapati
Jul 5, 2015

In response of siddharth singh

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...