A geometry problem by Roland Parijs
Geometry
Level
pending
Here is a nice problem. Given a rectangle with Length L , Height H and the angle of the diagonal ϕ, show that you can express the diagonal as √(A(tan(ϕ)+cot(ϕ)).
sqrt(H*L(H/L+L/H))=sqrt(H^2+L^2)
The area of a rectangle is H times L,diagonal is H divide by L!
A=L*H, Tan(ϕ)=H/L, Cot(ϕ)=L/H
Think of area (integral) and direction (differential)
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