A geometry problem by Nazmus sakib

Geometry Level pending

tan ⁡ − 1 x + cot ⁡ − 1 x + sec ⁡ − 1 x + cosec − 1 x = ? \large\tan^{-1} x + \cot^{-1} x + \sec^{-1} x + \text{cosec}^{-1} x =?

2 π 2\pi π 2 \dfrac{\pi}{2} π 4 \dfrac{\pi}{4} π \pi

Nazmus Sakib by Nazmus sakib , 24, Bangladesh

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Nazmus Sakib
Sep 19, 2017

We know that,

tan ⁡ − 1 x + cot ⁡ − 1 x = π 2 \tan^{-1} x + \cot^{-1} x = \dfrac{\pi}{2}

sec ⁡ − 1 x + cosec − 1 x = π 2 \sec^{-1} x + \text{cosec}^{-1} x = \dfrac{\pi}{2}

so,

tan ⁡ − 1 x + cot ⁡ − 1 x + sec ⁡ − 1 x + cosec − 1 x \tan^{-1} x + \cot^{-1} x + \sec^{-1} x + \text{cosec}^{-1} x

= π 2 + π 2 =\dfrac{\pi}{2}+ \dfrac{\pi}{2}

= 2 π 2 =\dfrac{2\pi}{2}

= π =\pi

2 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...