A geometry problem by Shivam Hinduja

Geometry Level pending

If sin x + sin y + sin z \sin x+\sin y+\sin z =3 ,

then find the value of

cos x + cos y + cos z \cos x+\cos y+\cos z


The answer is 0.

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1 solution

Sujoy Roy
Dec 16, 2014

As 1 sin θ 1 -1 \le \sin \theta \le 1 , here sin x = sin y = sin z = 1 \sin x=\sin y=\sin z=1 .

So, cos x = cos y = cos z = 0 \cos x=\cos y=\cos z=0 and cos x + cos y + cos z = 0 \cos x+\cos y+\cos z=\boxed{0} .

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