Loc(K)i and trigonometry

Geometry Level pending

The equation of a circle that passes through ( 0 , 1 ) (0,1) and ( 2 , 3 ) (2,3) and has its centre on the equation of locus of point which is equidistant from ( 1 , 1 ) (-1,1) and ( 4 , 2 ) (4,-2) is x 2 + y 2 + 2 g x + 2 f y + c = 0 x^2+y^2 + 2gx + 2fy + c = 0 .

If tan 1 ( 2 g ) + tan 1 ( 2 f ) + tan 1 ( c ) = tan 1 ( A ) \tan^{-1} (2g) + \tan^{-1} (2f) + \tan^{-1}(c) = \tan^{-1}(A) , where A A can be written in the form of a b \dfrac ab , where a a and b b are coprime positive integers, find a + b a+b .


The answer is 93.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Ahmad Saad
Mar 29, 2016

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...