SAT Properties of Triangles

Geometry Level 2


In the figure above, which of the following is the value of z z expressed in terms of x x and y ? y?

(A) 180 x y \ \ 180-x-y
(B) x + y + 180 \ \ x+y+180
(C) x + y 180 \ \ x+y-180
(D) x + y \ \ x+y
(E) 360 x y \ \ 360-x-y

A B C D E

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2 solutions

Tatiana Georgieva Staff
Feb 23, 2015

Correct Answer: C

Solution 1:

Tip: The measure of an exterior angle of a triangle equals the sum of the measures of the two non-adjacent interior angles.
B A C \angle BAC and x \angle x are supplementary angles. Therefore, their measures add to 18 0 180^\circ and

m B A C = 180 x . m\angle BAC = 180-x.

y \angle y is exterior, and therefore its measure equals the sum of the measures of the two remote interior angles:

y = m B A C + z y = 180 x + z x + y 180 = z \begin{aligned} y &= m\angle BAC + z\\ y &= 180-x + z\\ x+y-180 &= z\\ \end{aligned}

Solution 2:

Tip: The measures of the angles in a triangle add to 18 0 . 180^\circ.
B A C \angle BAC and x \angle x are supplementary angles. B C A \angle BCA and y \angle y are supplementary angles too. From the definition of supplementary angles, it follows that

m B A C = 180 x m\angle BAC = 180-x and
m B C A = 180 y m\angle BCA = 180-y

The measures of the angles in a triangle add to 18 0 . 180^\circ. Therefore,

m A B C + m B A C + m B C A = 180 m A B C = 180 m B A C m B C A z = 180 ( 180 x ) ( 180 y ) z = 180 180 + x 180 + y z = x + y 180 \begin{array}{r c l} m\angle ABC + m\angle BAC + m\angle BCA &=& 180\\ m\angle ABC &=& 180- m\angle BAC - m\angle BCA\\ z &=& 180 - (180-x) - (180-y)\\ z &=& 180- 180 + x - 180 + y \\ z &=& x + y - 180\\ \end{array}



Incorrect Choices:

(A)
If you think that x , y , x, y, and z z add to 180 , ^\circ, you will get this wrong answer. x x and y y are exterior, and not interior, angles.

(B)
You will get this wrong answer if in Solution 1 you add 180 to both sides instead of subtract it from both sides, like this:

y = 180 x + z x + y + 180 = z mistake: added instead of subtracted \begin{aligned} y &= 180-x + z\\ x+y \fbox{+}180 &= z \quad \text{mistake: added instead of subtracted}\\ \end{aligned}

or if in Solution 2 you add m B C A m\angle BCA to both sides instead of subtract it, like this:

m A B C + m B A C + m B C A = 180 m A B C = 180 m B A C + m B C A mistake: added, instead of subtracted z = 180 ( 180 x ) + ( 180 y ) \begin{aligned} &m\angle ABC + m\angle BAC + m\angle BCA =180\\ &m\angle ABC = 180- m\angle BAC \fbox{+} m\angle BCA \quad \text{mistake: added, instead of subtracted}\\ &z = 180 - (180-x) \fbox{+} (180-y)\\ \end{aligned}

(D)
If you apply to z \angle z the theorem which states that the measure of an exterior angle in a triangle equals the sum of the measures of the two nonadjacent interior angles, you will get this wrong answer. Note that z \angle z is an interior angle, and x \angle x and y \angle y are exterior angles.

(E)
This wrong choice is the sum of the measures of B A C \angle BAC and B C A . \angle BCA. It is offered to confuse you.

Ruslan Abdulgani
Feb 23, 2015

x = z+180-y, or z= x+y – 180.

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