Does Google Have an Answer for This?

Geometry Level 5

The white ring, blue small circle, and tri-colored big circle are all cocentric at point O. Point A is moving around the circumference of the small blue circle and point B is moving around the circumference of the large circle at a different angular velocity. When O, A, and B are co-linear, segment A B \overline{AB} has a length of 4. When the measure of O A B = 90 \angle{OAB}=90 ( A B \overline{AB} is tangent to the smaller circle), segment A B \overline{AB} has a length of 8. Point P is stationary at an arbitrary position on the outside circumference of the white ring. If the minimal distance between points A and P is 1, find the area of the yellow sector.

Assume:

The yellow, blue, and green sectors are congruent.

Points P,A,B stay on their respective circumferences.


The answer is 53.41.

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1 solution

Trevor Arashiro
Nov 1, 2014

image image

By Pythagorean theorem, we get R 2 = ( R 4 ) 2 + 64 R = 10 R^2=(R-4)^2+64\Rightarrow R=10 . Thus the radius of the Small circle is 6.

The white ring adds 1 unit to the radius of the blue circle, thus the area of the blue+white sectors = 49 π 49\pi . Also, the area of the big circle = 100 π 100\pi

The area of the large circle minus 49 π 49\pi will yeild the combined areas of the green, yellow, and red sectors. Since they are congruent, the yellow region has 1/3 this area.

100 π 49 π 3 = 17 π 53.41 \therefore \dfrac{100\pi-49\pi}{3}=17\pi\approx 53.41

Nice approach in finding R. Rest is simple.

Niranjan Khanderia - 5 years, 11 months ago

Same solution!!!!

Rwit Panda - 5 years, 5 months ago

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