A geometry puzzle
Points A and C lie on a line. Point B is equidistant from .A and .C. Point P lies on a line perpendicular to AC that intersects .A. PB and BC are collinear. |AC| = 2 and |BC| = . What is the area of the triangle whose vertices are .P, .B, and the midpoint of AC?
The answer is 1.
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1 solution
The area of the triangle is 2(base) * 1(height) * 1/2 = 1.