A Geometry Test #2

Geometry Level 2

Given a triangle ABC satisfying B ^ − C ^ = 2 0 o \widehat{B}-\widehat{C} = 20^{o} . The bisector of the angle A ^ \widehat{A} meets BC at D. Find angle A D C ^ \widehat{ADC} in degrees.

Part 1


The answer is 100.

Tin Le by Tin Le , 15, Vietnam

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1 solution

Dan Czinege
May 11, 2019

Angle |DAC|=(180°-B-C)/2
So the angle |ADC|=180°-C-|DAC|
|ADC|=90°+(B-C)/2=90°+20°/2=100°

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