A probability problem by A Former Brilliant Member
Probability
Level
pending
In how many ways can five boys and four girls be seated in a row, so that no two girls are together?
The answer is 43200.
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1 solution
Let seat all the boys leaving a place beside them. Now 5 boys are there and 4 girls. But now all total there would be 6 places for girls . So they can be seated in 6P4 ways again boys can be arranged in themselves by 5! ways Hence 6P4 x 5! =.43200