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arcs in(√n-√(n-1))/√{n(n+1) =arcsin[{√(1/n) √(n/(n+1))-√((n-1)/n) 1/√(n+1) Now take1/√n as sina and 1/√(n+1)as sinb. Now it will continue as a telescopic series. First we get arcs in(1) and last we getarcsin(0). Then its solved.