A GP in one AP

Algebra Level 3

3 , 4 , 6 , 10 , 18 , 34 , 3,\quad 4,\quad 6,\quad 10,\quad 18,\quad 34, \ \ldots

What is the 1 1 th 11^{\text{th}} term in the above sequence?


The answer is 1026.

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3 solutions

John Facistol
Nov 15, 2014

The general expression for this sequence is : 2^n + 2 where n = integer numbers starting from 1.

Pushpesh Kumar
Oct 7, 2014

This is a mental ability problem.

The series is like this,

3 3 3 + 2 0 = 4 3+2^{0}=4 4 + 2 1 = 6 4+2^{1}=6 6 + 2 2 = 10 6+2^{2}=10 10 + 2 3 = 18 10+2^{3}=18 18 + 2 4 = 34 18+2^{4}=34 . . . . . . . . . . . . . . . . . . . . ....................

Keep writing the numbers. The 10th term will be 258 + 2 8 = 514 258+2^{8}=514

Hence, the answer will be 514 + 2 9 = 514 + 512 = 1026 514+2^{9}=514+512=\boxed{1026}

Cesar Conterno
Oct 6, 2014

4-3=1=2° 6-4=2=2¹ 10-6=4=2² 18-10=8=2³ 34-18=16=2.2³

11th= 3+ (1+2+4+8+16+32+64+128+256+512)= 1026

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