Which tires on this bus are bearing the most load assuming the mass of the bus is evenly distributed from front to back?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The front tire is pretty close to the nose of the bus. Let L be the length of the bus, let W be the bus weight, let F be the force exerted by the rear tire, and let D be the distance of the rear tire from the front. The torques about the front of the bus must cancel each other:
W 2 L = F D F = W D L / 2
From the picture, it is evident that D L / 2 is about 0 . 7 or 0.8. Therefore:
0 . 7 W ≤ F ≤ 0 . 8 W
Since the forces exerted by the two tires must sum to W , it is clear that the force exerted by the rear tire must be greater.