A hint for my previous problem.

Level 2

I saw that a lot of people have got my recently posed problem Rotating rod in magnetic field wrong. I believe they have answered 0 0 . One gets 0 0 if he assumes magnetic field constant in whole region inside metallic ring(in red) having radius a < < r a << r . The same image is uploaded again :

Actually, the magnetic field changes its value, and its expression can be obtained by aproximations. The magnetic field at a distance x from center ( x < < r x <<r ) can be written as B B 0 ( 1 + k 2 ( x r ) n ) B \approx B_{0} \bigg(1+ \dfrac{k}{2} \bigg(\frac{x}{r} \bigg)^n \bigg) , where B 0 B_0 is magnetic field at center( O O ) of the circular current carrying loop. Find k + n k+n .


The answer is 5.

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1 solution

Jatin Yadav
Apr 10, 2014

B B 0 ( 1 + 3 2 ( x r ) 2 ) \displaystyle B \approx B_{0} \bigg( 1+ \dfrac{3}{2} \bigg(\frac{x}{r}\bigg)^2 \bigg) . I have posted solution to that problem. Visit Rotating Rod In Magnetic Field

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