A house? or not

Geometry Level 2

Triangle A B C ABC is a right triangle with A = 9 0 \angle A = 90^\circ . Point W W on segment A B AB , X X on A C AC , and points Y Y and Z Z on B C BC are such that W X Y Z WXYZ is a square.

If B Z = 6 BZ = 6 and Y C = 8 YC = 8 (the remaining Y Z YZ is a side of the square), find the area of the square W X Y Z WXYZ .


The answer is 48.

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2 solutions

Chew-Seong Cheong
May 28, 2021

Let the side length of square W X Y Z WXYZ be a a . Then the area of square W X Y Z WXYZ is a 2 \blue{a^2} . We note that C X Y \triangle CXY and B W Z \triangle BWZ are similar and X C Y = B W Z = θ \angle XCY = \angle BWZ = \theta . Then

tan θ = a 8 = 6 a a 2 = 48 \tan \theta = \frac a8 = \frac 6a \implies \blue{a^2} = \boxed{48}

Saya Suka
May 27, 2021

Should be "If BZ = 6 and YC = 8" in the problem statement. Anyway, we have the ratio
BZ / ZW = XY / YC
6 / s = s / 8
s² = 6 × 8 = 48


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