A Game of Murderers

Logic Level 3

Imagine that there is a group of ruthless murderers. They play a game. The game was about killing people. The murderers make a circle. One murderer starts first. He kills the next person who is not dead. The rest (who are not dead) do the same. The game stops when only one person is alive (the winner).

This is a example of murderers playing

Who will win if there are 101 murderers?

Hint: think of 2 x 2^{x} if x is a whole number.


The answer is 75.

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2 solutions

When total number of murderers is of the form 2^p, the winner position is 1, and then the position increases by 2 units for increase in the total number by 1 until it becomes of the form 2^(p+1). Since 101=2^6+37, therefore the winning position is 1+(37)(2)=1+74=75

Vedant Saini
Apr 1, 2019

@sucheng zhu

You seem to make a lot of your problems based on youtube videos!!!

Here is a link to a Numberphile video which explains the answer in a very lucid manner.

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