Grooves through a sphere

A sphere, as shown in the image is placed on a horizontal surface with three grooves drilled into it from point A A to points B , C , B, C, and D . D.

A C \overline{AC} is a diameter to the sphere, while A B \overline{AB} and A D \overline{AD} are chords, such that:

B A C = θ D A C = 2 θ . \begin{aligned} \angle BAC &= \theta\\ \angle DAC &= 2\theta. \end{aligned}

An object of mass M M is dropped thrice, each time through each groove, and the time taken for it to emerge out of the groove is measured.

Now, let a : b : c a:b:c (where a , b , a,b, and c c are coprime integers) be the ratio of the respective times that the object takes to exit through grooves A B \overline{AB}\, A C \overline{AC} and A D . \overline{AD}. Find a + b + c . a+b+c.

Details and Assumptions

  • Gravity is constant at g = 9.8 m/s 2 g = 9.8\text{ m/s}^2 vertically downwards at all times.
  • The grooves have negligible friction, and the object is considered to be point sized.

Please do note that this problem was taken from a teacher of mine.


The answer is 3.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jamie Hilditch
Feb 5, 2015

AC is a diameter so A B C \angle ABC and A D C \angle ADC are both right angles

Let AC=x Then AB=x cosθ and AD=x cos2θ

Resolving gravity in the direction of motion

For AC acceleration=g

For AB acceleration=g cosθ

For AD acceleration=g cos2θ

s = u t + a t 2 2 s=ut+ \frac{at^{2}}{2}

u = 0 t = 2 s a u=0 ∴t=\sqrt\frac{2s}{a}

∴in all cases t = 2 x g t=\sqrt\frac{2x}{g} a : b : c = 1 : 1 : 1 ∴a:b:c=1:1:1 and a + b + c = 3 a+b+c=3

Although, the answer can be found much quicker by considering the case θ=0 where the three grooves are the same

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...