A large prime number!

Level 2

Find the sum of all integer values of n n such that the number n 4 + 4 n^4+4 is a prime number.


The answer is 0.

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3 solutions

Victor Loh
Jan 4, 2014

Let x x be a value of n n that satisfies the equation.

Then x -x will also satisfy the equation as any number a a squared = = a -a squared.

Hence the sum of all integer values of n n will cancel out to be 0 \boxed{0} .

Look, Victor Loh i think this would have been a better solution for this problem: From Sophie Germain Identity we know that n 4 + 4 n^4+4 can be factored as followed:

n 4 + 4 = ( n 2 + 2 n + 2 ) ( n 2 2 n + 2 ) n^4+4=(n^2+2n+2)(n^2-2n+2) . But n 4 + 4 n^4+4 is a prime number and therefore one of the factors must be equal to 1 1 .Thus, we have two cases: First case:

n 2 + 2 n + 2 = 1 n^2+2n+2=1 \rightarrow n = 1 n=1

Second case:

n 2 2 n + 2 = 1 n^2-2n+2=1 \rightarrow n = 1 n=-1 . Thus, n = ± 1 n=\pm{1} and the sum is 0 \boxed{0} .

Lorenc Bushi - 7 years, 5 months ago

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You made a small mistake, In the FIRST CASE, it should be n = ( 1 ) n=(-1) and in the SECOND CASE, it should be n = 1 n=1 . Correct me if I'm wrong.

Prasun Biswas - 7 years, 5 months ago

Right, Loh, this problem becomes trivial if "integer values" includes negative integers. Otherwise, it's a harder problem. Methinks the problem should have asked for only positive integer values.

Michael Mendrin - 7 years, 1 month ago

Yes I agree. Thanks

Victor Loh - 7 years, 5 months ago

n 4 + 4 n^{4}+4

( n 2 + 2 ) 2 4 n 2 (n^{2}+2)^{2}-4n^{2}

( n 2 + 2 n + 2 ) ( n 2 2 n + 2 ) (n^{2}+2n+2)(n^{2}-2n+2)

A prime number has only two factors, 1 1 and the number itself. So, we have two cases:

  1. If n 2 + 2 n + 2 = 1 n = 1 n^{2}+2n+2=1\implies n=-1

  2. If n 2 2 n + 2 = 1 n = 1 n^{2}-2n+2=1\implies n=1

Therefore, the sum of all integer values of n n is 0 \boxed {0}

Prasun Biswas
Jan 5, 2014

Since n n is raised to the power 4, if for any positive value of n n , we get n 4 + 4 n^{4}+4 as a prime no., also the negative value of n n satisfies that n 4 + 4 n^{4}+4 is a prime no. When all the values of n n that satisfies n 4 + 4 n^{4}+4 is a prime number are added, the corresponding positive and negative values of n n cancel out each other and the resultant sum is 0 \boxed{0}

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