If we take a certain 3-digit integer and reverse its digits to form another 3-digit integer, then the sum of these two numbers is always divisible by which of the following numbers?
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Let us consider a 3 digit number 1 0 0 a + 1 0 b + c
Reversing it the number will become 1 0 0 c + 1 0 b + a
Adding the numbers,
1 0 1 a + 2 0 b + 1 0 1 c
Since nothing can be taken as common, hence there is no such number that divides the sum.