A Little Gravity Never Hurts

Classical Mechanics Level 1

If a mass m m is placed close to the Earth's surface, the force on it is m g mg .

We know that the Earth has a gravitational field, E E that exerts a force F F on the mass and is defined by the following relationship:

E E = F m \frac{F}{m}

Given F F = m g mg , we get:

⟹ \implies E E = g g

Thus, the intensity of gravitational field near the Earth's surface is equal to the acceleration due to gravity.

Does this mean E E and g g are the same physical quantity having equal magnitude and direction?

False True

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1 solution

In this situation, they may be equal in magnitude and direction, but E E and g g are entirely different physical quantities.

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