× 7 □ □ □
What is the product of all the missing digits?
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× 7 8 9 2
⇒ 8 × 9 × 2 = 1 4 4
Since they are all single digits, the only possibility is 9x8=72. Other answers you may have thought of was 7x10, 7x11 etc. but a quick realisation is that they are all single digits.
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Relevant wiki: Arithmetic Puzzles - Fill in the Blanks
The long multiplication tells us that we want to find 2 single digit positive integers such that their product is a 2-digit integer with 7 as its tenth digit.
So the possible value of this product can take the value 7 0 , 7 1 , 7 2 , … , 7 9 .
The product cannot be 70 because 7 0 = 7 × 1 0 cannot be expressed as the product of 2 single digit positive integers. Likewise, we can rule out 74, 75, 77 and 78 as well.
The product cannot be 71 because 7 1 = 1 × 7 1 is a prime number, and so it cannot be expressed as the product of 2 single digit positive integers. Likewise, we can rule out 73 and 79 as well.
The product can be 7 2 = 8 × 9 because it can be expressed as product of 2 single digit positive integers.
Hence, the long multiplcation is
× 7 8 9 2
with the positions of the digits 8 and 9 to be interchangeable. Thus, our answer is 8 × 9 × 2 = 7 2 × 2 = 1 4 4 .