An algebra problem by Hemant Kumar
Algebra
Level
3
A watermelon weighs 5 kg. it contains 99% water. now put it on drying room for some time. now the water reduces to 98%. what will be the weight of water melon after drying?
none of these
2500gm
4950gm
4100gm
4900gm
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1 solution
Before drying, the watermelon has 99% water, it means 1% is "real watermelon" = 1% x 5kg = 0.05 kg. After drying, the new watermelon has 98% water, it means that 0.05 kg of "real watermelon" is 2% of the new watermelon. Therefore, we have 100% new watermelon = 0.05kg / 2% = 2.5 kg.