Chocolate for wrappers

77 wrappers may be split into 15 packs of 5 wrappers, and 2 wrappers off-pack . Here, you will get 15 wrappers . Then, from the 15 wrappers, it may be split into 3 packs of 5 wrappers, which give you 3 more wrappers . 3 wrappers is not sufficient by its own, so you combine it with 2 wrappers off-pack to redeem one more chocolate . Therefore, you will get a total of 15+3+1 = 19 chocolates with that 77 wrappers.

Let the number of chocolates that can be eaten in total be $x$ .

The number of chocolates that can be bought by wrappers is $\cfrac{x}{5}$ .

$x=\cfrac{x}{5}+77$

$\cfrac{4x}{5}=77$

$\cfrac{x}{5}=\cfrac{77}{4}$

According to the question, we are looking for $\cfrac{x}{5}$ .

So,the number of chocolates that can be bought by wrappers is 19, upon taking the integer value of $\cfrac{77} {4}$

Isn't it amazing!