Can a total of 720 be achieved using 6 0s? If so, how many different operators are required to achieve this?
If the number of different operators required are , compute n-1
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720
(0!+0!+0!+0!+0!+0!)! =(1+1+1+1+1+1)! =(6)! =6! is 6 * 5 * 4 * 3 * 2 * 1 = 720
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