In preparation for tomorrow

Logic Level 2

Using any mathematical operation, try to make the following equation true:

1 2 3 4 = 30 \Large 1 \ \ 2 \ \ 3 \ \ 4 \ \ = \ \ 30

Is it possible?

Details

  • You are allowed addition, subtraction, multiplication, division, power, parentheses and square roots.

  • You are allowed to use only one of the digits (i.e. 1, 2, 3, 4) up to two times but the order in which these digits appear in your answer must be the same as in the question. For example, 3 ( 1 + 2 + 3 + 4 ) 3*(1+2+3+4) is NOT an acceptable solution.

  • No combining of the digits is allowed. For example, you can't merge 1 and 2 to get 12.

No Yes

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1 solution

Noel Lo
Jun 28, 2016
  • 1 1 + 2 3 4 = 2 + 8 4 = 2 + 32 = 30 -1-1+2^3*4=-2+8*4 = -2+32=30 where the one is repeated.
  • ( 1 + 2 + 2 ) 3 4 (1+2+2)*3*\sqrt{4} or ( 1 + 2 2 ) 3 4 (1+2*2)*3*\sqrt{4} or ( 1 + 2 2 ) 3 4 = ( 1 + 4 ) 3 2 = 5 3 2 = 30 (1+2^2)*3*\sqrt{4} = (1+4)*3*2 = 5*3*2=30 where the two is repeated.
  • ( 1 + 2 ) 2 ( 3 + 4 ) = 3 2 ( 3 + 2 ) = 6 5 = 30 (1+2)*2*(3+\sqrt{4}) = 3*2*(3+2) = 6*5=30 where the two is repeated.
  • ( 1 + 2 ) ( 2 + 3 ) 4 = 3 5 2 = 30 (1+2)*(2+3)*\sqrt{4} = 3*5*2=30 where the two is repeated.
  • 1 2 3 ( 3 + 4 ) 1*2*3*(3+\sqrt{4}) or ( 1 + 2 + 3 ) ( 3 + 4 ) = 1 2 3 ( 3 + 2 ) = 6 5 = 30 (1+2+3)*(3+\sqrt{4})=1*2*3*(3+2) = 6*5=30 where the three is repeated.

This question set you posted recently is terrific!

Akhash Raja Raam - 4 years, 11 months ago

You can do that with 4 repeating also anyway.

Namely , with 4 repeating at the end 1 * 2^3 * 4 - 4sqrt = 1 * 8 *4 - 2 = 32 -2 =30 anyway.

A A - 4 years, 11 months ago

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That's awesome too!

Akhash Raja Raam - 4 years, 10 months ago

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haha. Thanks.

A A - 4 years, 10 months ago

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