ROUND THE STAR
A star S is being orbited by a planet P such that the planet rotates around itself once every 0.1 earth days. It is observed that P completes 196 rotations around itself by the time it completes 1 revolution around S . If the planet's sense of rotation and revolution is in the same direction, its orbital period (in earth days) would be .
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1 solution
The rotation period of the star is 0.1 Earth days = 0.1 × 24 = 2.4 hrs
The star completes 196 rotations for 1 revolution around the star S.
So, the revolution period with respect to Earth hours is 196 × 2.4 = 470.4 hours
Now, if one Earth day is 24 hours long, then the revolution period w.r.t Earth days is 2 4 4 7 0 . 4 = 19.6 Earth days.