Statements have the right to be wrong

Number Theory Level 3

Three statements are defined below.

p : p: 4 is an even prime number.

q : q: 6 is a divisor of 12.

r : r: The HCF of 4 and 6 is 2.

Which statement among the options is a true statement?

( p ∨ q ) ∧ ∼ r ( p \vee q ) \wedge \sim r p ∧ q p \wedge q ∼ ( q ∧ r ) ∨ p \sim (q \wedge r) \vee p ∼ p ∨ ( q ∧ r ) \sim p \vee ( q \wedge r )

Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

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2 solutions

We have p ≡ F p\equiv F , q ≡ T q\equiv T and e ≡ T e\equiv T . So we can realize that: p ∧ ( q ∨ r ) ≡ F ∨ ( T ∧ T ) ≡ T ~p\wedge(q\vee r) \equiv ~F\vee(T\wedge T) \equiv T

1 Helpful 0 Interesting 0 Brilliant 0 Confused

P is wrong so ~p is true. Rest of the two statements are true. So option 1 fits

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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