The lonely diode

A diode is characterized by its I-V curve similar to the one above.

Consider a diode whose dynamic resistance is given by

r d y n ( i ) = V d ( i + β ) 2 β { r }_{ dyn }(i)=\frac { { V }_{ d } }{ { (i+\beta ) }^{ 2 }\ }\beta
where i i is the current and β \beta and V d { V }_{ d } are characteristics of the diode.

This diode is connected from terminal to terminal with a conducting wire forming a loop. This planar loop has area A A and is kept in a magnetic field B B , normal to its plane.

Find the average power dissipation (in nano-Joules ) across the diode.

Given:

  • V d = 0.9 V { V }_{ d }=0.9 V

  • β = 0.1 A \beta = 0.1 A

  • B = B 0 c o s ( 100 t ) B = { B }_{ 0 }cos(100t) with B 0 = 1 μ T { B }_{ 0 }= 1\mu T

  • A = 1 m 2 A = 1 m ^2


The answer is 0.278.

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