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nice solution
It’s easy to see the pattern n × ( n + 1 ) , therefore we use it to search the regulations. P = 2 × 6 × 1 2 × 2 0 × ⋯ × 7 2 = 1 × ( 1 + 1 ) × 2 × ( 2 + 1 ) × 3 × ( 3 + 1 ) × ⋯ × 8 × ( 8 + 1 ) = 1 × 2 × 2 × 3 × 3 × 4 × ⋯ × 8 × 9 = 1 × 2 × 3 × 4 × ⋯ × 8 × 3 = 1 2 0 9 6 0
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P = 2 × 6 × 1 2 × 2 0 × ⋯ × 7 2 = 2 × 6 × 1 2 × 2 0 × ⋯ 7 2 = ( 1 × 2 ) × ( 2 × 3 ) × ( 3 × 4 ) × ( 4 × 5 ) × ⋯ × ( 8 × 9 ) = 1 × 2 2 × 3 2 × 4 2 × 5 2 × ⋯ × 8 2 × 9 = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 3 = 1 2 0 9 6 0