A Lucas Conjecture

In a distant empire, quarry workers are given a choice of multiple square boxes with various integer lengths and a height of 1 to pack cubes of granite, each of volume 1, into.

They are taking these blocks to the capital city of Sacul, where they will construct a pyramidal monument for the emperor Edouard II.

The pyramid is constructed with a square base ^{*} such that the center of each cube above aligns vertically with each point that four cubes meet beneath. Every block of granite must be used.

Given the above conditions, what is the maximum length of square box the quarry workers can choose?

^{*} Note: The pyramid should look something like this:


The answer is 70.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jake Lai
Dec 28, 2014

This problem is known as the cannonball problem .

I'll leave posting a proof by elementary means that the only solutions to x ( x + 1 ) ( 2 x + 1 ) 6 = y 2 \frac{x(x+1)(2x+1)}{6} = y^{2} are (1,1) and (24,70) till the morrow.

I've stumbled upon only one elementary proof by Anglin, which was terribly long and, quite frankly, pretty boring.How did you prove it?

Bogdan Simeonov - 6 years, 4 months ago

Log in to reply

"The morrow" is a day that never comes.

Jake Lai - 6 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...