A 20g bullet moving at 300m/s stops after penetrating 3 cm of bone . Calculate the average force exerted by the bullet
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W = E 2 − E 1 F × s = 2 1 × m × ( v 2 2 − v 1 2 ) F × 3 × 1 0 − 2 = 2 1 × 2 0 × 1 0 − 3 × ( 3 0 0 2 − 0 2 ) F = 3 9 × 1 0 4 F = 3 × 1 0 4
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I applied formula integral(F.ds) / integral(ds) , and wrote F = m . v .dv/ds , which cancels ds in numerator , and integrate it woth proper limits of 300m/s as lower limit and 0 as higher limit, also convert the g to kg, cm to metre.