A classical mechanics problem by Ajay Venugopal

Classical Mechanics Level 5

Find the force required to move a train of mass 2000 quintal up an incline of 1 in 50 with a acceleration of 2m/s , the force friction being 0.5N/Quintal


The answer is 440200.

Ajay Venugopal by Ajay Venugopal , 22, India

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1 solution

Swagat Panda
Oct 18, 2016

F r e q u i r e d = m g sin ⁡ θ + m a + F f r i c t i o n , where: m = 2000 × 100 kg = 200 , 000 kg a = 2 m s − 2 sin ⁡ θ = 1 50 g = 9.8 m s − 2 F f r i c t i o n = 0.5 × 2 , 000 = 1000 N F_{required}=mg\sin{\theta}+ma+F_{friction} \text{, where: } \\ m=2000\times100 \text{ kg }=200,000\text{ kg } \\ a=2ms^{-2} \\ \sin{\theta}=\dfrac{1}{50} \\ g= 9.8ms^{-2} \\ F_{friction}=0.5 \times 2,000=1000 \text{ N }

Putting these values in the above equation we get:

F r e q u i r e d = ( 200 , 000 ) ( 9.8 ) ( 1 50 ) + ( 200 , 000 ) ( 2 ) + 1000 = 39 , 200 + 400 , 000 + 1000 = 440 , 200 N F_{required}=(200,000)(9.8)\left(\dfrac{1}{50}\right)+(200,000)(2)+1000=39,200+400,000+1000=\boxed{440,200 \text{ N} }

2 Helpful 0 Interesting 0 Brilliant 0 Confused

@Josh Silverman isn't it very highly rated question should be level 2 atmost , masses are so much given , that is the only reasong people migh be failing it !

A Former Brilliant Member - 4 years, 5 months ago

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Please use the reports to handle things like this.

Josh Silverman Staff - 4 years, 5 months ago

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