A classical mechanics problem by sid leo
A bent tube is lowered into A water stream as shown in Figure......the velocity of de stream Relative to the tube is v=2.5 m/s.......The closed upper end Of tube is located at a height h0=12 cm has a small orifice.....To wat height h will de water spurt?? In centimetres take g=9.8 m/s
The answer is 20.
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1 solution
As the orifice is smaalll......you can take de fluid to be as a point sized particle from de definition of velocity of efflux......
Let de spurt velocity be u=(2gh)^.5 Nw as de particle movess frm a height to level h0 V^2 - u^2 = 2g(h0+h1).......h1 is de height frm tube to de water surface.......and h1<<<h0 => {(v^2)/2g} - h0 = h Substituting de values of v,g,h we get h0=19.886≈20