A ball is thrown leftward from the left edge of
the roof, at height
h
above the ground. The ball hits the ground
2s
later, at distance =
24m
from the building.
Find h .
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-h = vo sinθ t - 1/2 g t^2...(1) vo cosθ t = 24. put t = 2s vo cosθ = 12 m = v' v'^2 - (vo sinθ)^2= 2 10 h.......(2) 144 - (vo sinθ)^2 = 20 h. From the above equation you can see that h cannot be 8. Now try 4. We get vo*sinθ = 16. It satisfies the equation(1)