A classical mechanics problem by Vikram Singh
A ball is thrown leftward from the left edge of
the roof, at height
h
above the ground. The ball hits the ground
2s
later, at distance =
24m
from the building.
What is the maximum height the ball can reach?
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1 solution
Horizontal component of velocity = Vcos(45)
Horizontal distance covered in 2s is 24m
therefore as horizontal component is constant then :-
V cos(45)=24/2
V=16.97 m/s
For vertical motion
V^2=U^2+2gh
(V sin45)^2=2(10)h
h=7.2m