A mixture of Organic and Physical Chemistry

Chemistry Level 3

The number of statements given below which are correct with respect to the given picture above are $n.$

In the formation of $D$ from $C,$ ring expansion takes place.
The product $D$ is cyclopentanone.
The product $D$ is $\alpha,\beta$ - unsaturated cyclopentanone.
The conversion of $B$ to $C$ can be carried out with $\text{LiAlH}_{4}.$

Evaluate $j= n^{3} + 4n^{2} + 4n,k= (n+2)!.$

At a given temperature, the total vapour pressure (in torr) of a mixture of volatile components $A$ and $B$ is given by $P_{\text{total}} = k - j\cdot X_{B}.$

Evaluate the magnitude of difference in vapour pressures (in torr) of pure components $A$ and $B.$

The answer is 75.

1 solution

A Former Brilliant Member
Feb 26, 2015

First of all I'm sorry since I can't draw the structures here .

The only the second statement is wrong , hence $n=3$ .

Hence $j=75,k=5!=120$ .

We all know that $P_{A}$ and $P_{B}$ have been calculated when they are in pure conditions

Let's consider that time when only component $B$ was present in the solution i.e. $X_{B}=1$ and $P_{Total} = P_{B}°$ , $P_{Total} = 120 - 75\cdot X_{B} \\ \therefore P_{Total} = 120-75 = 45$

Let's consider that time when only component $A$ is present in the solution i.e. $X_{B}=0$ and $P_{Total} = P_{A}°$ , $P_{Total} = 120 - 75\cdot X_{B} \\ \therefore P_{Total} = 120 - 0 = 120$

Therefore our answer is $|120-45|=75$ .

NOTE : $P_{Total}$ is independent of $X_{A}$ .

I am going to follow you. However why this question is so low pointed?? Its obviously not so easy.

Shyambhu Mukherjee - 5 years, 6 months ago

the lo w rating is because one can easily know that answer is j which can be found by knowing the value of n which again has 4 possibilities and we have 3 tries

Satyabrata Dash - 3 years ago

Lol not that way First we have cyanohydrin formation.followed by base-catalysed hydrolysis to give both -OH and -COOH groups Now reduction by H2/No yields the cyclobutyl ring along with -OH and -Ch2OH Now HN02 performs the job of generating a carbocation along with an alkoxide(stabilises charge separation),ring expands to reduce angle strain, a ketone is formed and the carbocation soon forms the olefinic-double bond Leading to cyclopentane with Alpha-Beta unsaturation Hence we have 3 statements True (LAH reduces carboxyl groups to hydroxyl groups so we're good :P Hence n=3 And j=75 is just computation Cute problem overall

Suhas Sheikh - 3 years ago

A mixture of Organic and Physical Chemistry

The answer is 75.

1 solution

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