Cricc buzz......

Algebra Level 4

There are two batsman A and B who are playing a 50 over match. A keeps the strike for the first five overs. B keeps the strike for the next five overs. This process goes on and on till the end. Find the maximum possible runs scored by A and B.

Details and Assumptions

1) The maximum possible score of a batsman in a ball is 6 and he can never score 5 in any ball.
2) There are 6 balls in an over.
3) The batsman can face a ball only if he is at the striker's end when the ball is being bowled. 
4) If the batsman scores 2,4 or 6 he still remains at the striker's end.If he scores 1 or 3 then he has to move to the non-striker's end.
5) If the batsman is at the striker's end at the end of an over then he has to move to the non-striker's end and can come back to the striker's end only if his fellow batsman scores 1 or 3 in that ball or his fellow batsman plays the entire over and is at the striker's end when the over ends.

820 and 824 820 and 820 824 and 820 None of the above

2 solutions

Daman Deep Singh
Apr 9, 2016

As Kshitij Alwadhi showed Player $A$ can score $840$ runs (maximum).

But Player $B$ ,having the opportunity to play the last ball , can hit a six on the last ball so he can score $843$ runs.(maximum)

So, the maximum score is $840+843=1683$

Hence, the answer is none of these

Kshitij Alwadhi
Sep 25, 2015

For player A: (Over 1) first 5 balls x 6 runs : 30 runs + 1 ball x 3 runs (to stay on strike) = 33 runs Repeat for the first 4 overs. In the 5th over he can score 6 balls x 6 runs = 36 runs . Total runs in 5 overs for batsman A : 33 x 5 + 36 =168 runs This will happen 5 times (from overs 1-5; 11-15; 21-25; 31-35; 41-45. Therefore total runs for batsman A = 168 x 5 = 840 runs.

For batsman B: Do the same thing as the result will not differ.

Therefore, the answer is None of these!

Cricc buzz......

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