A Musical Question!
Classical Mechanics
Level
3
A loud speaker produces a musical sound by means of oscillations of a diaphragm whose amplitude is limited to 1 micrometer. The frequency at which magnitude of acceleration of diaphragm becomes equal to acceleration due to gravity is ... Hz
Image credit: Wikipedia Chetvorno
498
398
698
598
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1 solution
We have, acceleration, 4π²f²a=g ( acceleration = w²a where w= angular velocity , w=2πf(f=frequency), and 'a' is the amplitude). On solving, we get f=498.486 Hz ≈ 498 Hz.