Find the value of .
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Euler found the sum of the reciprocal of squares to be Pi^2/6, so LHS = 1/a * Pi^2/6. The definite integral is a standard form, and it is arcsin (x/2) evaluated between the limits of 1 and 0. (The substitution x = 2 cos (theta) simplifies the expression to -Integral d(theta) from Pi/3 to Pi/2.) RHS = Pi/6 = 1/a * Pi^2/6. Therefore, a = Pi.